Sum of squares of a given list of numbers

Sum of squares of a given list of numbers

THEORY:

The sum of the series (1^2 + 2^2 + 3^2 + ... + N^2) is

(N * (N + 1) * (2N + 1)) / 6

CODING:

#include<iostream.h>

#include<conio.h>

void main()

{

int a=1,sum=0,n;

clrscr();

cout<<"Enter a number:";

cin>>n;

while(a<=n)

{

sum=sum+a*a;

a++;

}

cout<<"The sum of square of n numbers is:"<<sum;

getch();

}

OUTPUT:

IIT-JAM

JEST

GATE

NET